J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    Forces exerted by a uniform electric field on an electron having mass \[{{m}_{e}}\]  and proton of mass \[{{m}_{p}}\]are represented as \[{{F}_{e}}\] and \[{{F}_{p}}\] respectively are related as

    A)  \[{{F}_{p}}={{F}_{e}}\]

    B)  \[\frac{{{F}_{e}}}{{{F}_{p}}}=\frac{{{m}_{e}}}{{{m}_{p}}}\]

    C)  \[\frac{{{F}_{e}}}{{{F}_{p}}}=\frac{{{m}_{p}}}{{{m}_{e}}}\]

    D)  \[\frac{{{F}_{e}}}{{{F}_{p}}}=\frac{m_{e}^{2}}{m_{p}^{2}}\]

    Correct Answer: A

    Solution :

    The force (F) on charge q due to electric field strength E is \[F=qE\] Given, E is uniform, hence \[{{F}_{p}}={{F}_{e}}\]


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