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J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    Ratio of the radii of the nuclei with mass numbers 8 and 27 would be

    A)  \[27/8\]        

    B)  \[8/27\]

    C)  \[2/3\]          

    D)  \[3/2\]

    Correct Answer: C

    Solution :

    The radii of a nuclei (R) varies with atomic number A as \[R=k{{A}^{1/3}}\] Given,     \[{{A}_{1}}=8,\,\,\,\,{{A}_{2}}=27\] \[\therefore \] \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{(8)}^{1/3}}}{{{(27)}^{1/3}}}=\frac{2}{3}\]


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