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J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    The metal ion in complex \[\underset{\scriptscriptstyle-}{A}\]has BAN identical to the atomic number of krypton. \[\underset{\scriptscriptstyle-}{A}\]is (At. no. of\[Cr=24,\,Fe=26,\,Pd=46\])

    A) \[[Pd{{(N{{H}_{3}})}_{6}}]C{{l}_{4}}\]

    B) \[[Cr{{(N{{H}_{3}})}_{5}}Cl]S{{O}_{4}}\]

    C)  \[N{{a}_{4}}[Fe{{(CN)}_{6}}]\]

    D)  \[{{K}_{3}}[Fe{{(CN)}_{6}}]\]

    Correct Answer: C

    Solution :

     \[EAN=Z-(ON)+2(CN)\] where,\[ON=\] oxidation number \[CN=\]coordination number \[Z=\]atomic number \[{{[Fe{{(CN)}_{6}}]}^{4-}}:\] \[EAN=26-(2)+2(6)\] \[=26-2+12=36\]


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