A) increases by \[20%\]
B) decreases by \[20%\]
C) increases by \[25%\]
D) decreases by \[25%\]
Correct Answer: C
Solution :
According to Boyle's law \[{{p}_{1}}\,{{V}_{1}}={{p}_{2}}\,{{V}_{2}}\] As the pressure is decreased by 20%, so \[{{p}_{2}}=\frac{80}{100}{{p}_{1}}\] \[{{p}_{1}}{{V}_{1}}=\frac{80}{100}{{p}_{1}}{{V}_{2}}\] \[{{V}_{1}}=\frac{80}{100}p{{V}_{2}}\] \[\therefore \] \[{{V}_{2}}\] percentage increase in volume \[=\frac{{{V}_{2}}-{{V}_{1}}}{{{V}_{1}}}\times 100\] \[=\frac{100-80}{80}\times 100=25%\]
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