A) Ethene
B) Propene
C) 1-butene
D) 2-butene
Correct Answer: D
Solution :
Ozonolysis involves the breaking of double bond and insertion of 0 atoms in place of double bond. Therefore, the structure of alkene. is as \[{{H}_{3}}C-\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,==\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,-C{{H}_{3}}\] \[\underset{2-\text{butene}}{\mathop{{{H}_{3}}C-CH=CH-C{{H}_{3}}}}\,\]
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