J & K CET Engineering J and K - CET Engineering Solved Paper-2008

  • question_answer
    An aqueous solution contains \[N{{i}^{2+}},C{{o}^{2+}}\]and\[P{{b}^{2+}}\]ions    at    equal concentrations. The solubility product of \[\text{NiS, PbS}\]and \[\text{CoS}\]in water at \[\text{25}{{\,}^{\text{o}}}\text{C}\]are \[\text{1}\text{.4}\times \text{1}{{\text{0}}^{-24}},\]and\[3\times {{10}^{-26}},\]respectively. Indicate which of these ions will be precipitated first and last   when   sulphide   concentration is progressively increased from zero?

    A)  NiS and PbS   

    B)  NiS and CoS      

    C)  CoS and NiS   

    D)  PbS and NiS

    Correct Answer: D

    Solution :

     For precipitation, ionic product > solubility product \[\therefore \]The metal sulphide with lowest \[{{K}_{sp}}(PbS)\]will precipitate out first because its ionic product will exceed its \[{{K}_{sp}}\]first and the metal sulphide with lowest\[{{K}_{sp}}(NiS)\] will precipitate out at last.


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