A) \[0\]
B) \[1\]
C) \[2\]
D) \[3\]
Correct Answer: C
Solution :
Let \[I=\int_{-\pi /2}^{\pi /2}{\frac{dx}{2\,{{\cos }^{2}}\frac{x}{2}}}\] \[=\int_{0}^{\pi /2}{{{\sec }^{2}}\frac{x}{2}dx}\] \[=\left[ 2\,\,\tan \frac{x}{2} \right]_{0}^{\pi /2}=2\]You need to login to perform this action.
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