A) \[\frac{4}{3}\mu F\]
B) \[\frac{24}{5}\mu F\]
C) \[9\,\mu F\]
D) \[5\,\mu F\]
Correct Answer: A
Solution :
Effective capacitance of \[{{C}_{2}}\] and \[{{C}_{3}}\] \[\frac{1}{C}=\frac{1}{2}+\frac{1}{2}\] \[\Rightarrow \] \[C=1\mu F\] 1 Now, \[{{C}_{1}}\] and C are in parallel, therefore effective capacitance \[C'\] \[C'=1+1=2\mu F\] Now, \[C'\] and \[{{C}_{4}}\] are in series, therefore, effective capacitance between points A and B \[\frac{1}{C''}=\frac{1}{2}+\frac{1}{4}=\frac{3}{4}\] \[\Rightarrow \] \[C''=\frac{4}{3}\mu F\]
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