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J & K CET Engineering J and K - CET Engineering Solved Paper-2008

  • question_answer
    If g is the acceleration due to gravity on the surface of earth, its value at a height equal to double the radius of earth is

    A)  \[g\]                

    B)  \[\frac{g}{2}\]

    C)  \[\frac{g}{3}\]              

    D)  \[\frac{g}{9}\]

    Correct Answer: D

    Solution :

    Acceleration due to gravity at a height h from the surface of the earth \[g'=g\frac{1}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\] Given,      \[h=2R\] \[\therefore \] \[g'=g\frac{1}{{{(1+2)}^{2}}}\] or \[g'=\frac{g}{9}\]


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