J & K CET Engineering J and K - CET Engineering Solved Paper-2008

  • question_answer
    On bombardment of \[{{U}^{235}}\] by slow neutrons, \[200\text{ }MeV\] energy is released. If the power output of atomic reactor is \[1.6\text{ }MW,\] then the rate of fission will be

    A)  \[5\times {{10}^{16}}/s\]     

    B)  \[10\times {{10}^{16}}/s\]

    C)  \[15\times {{10}^{16}}/s\]    

    D)  \[20\times {{10}^{-16}}/s\]

    Correct Answer: A

    Solution :

    Rate of fission \[=\frac{P}{energy\,for\,fission}\] \[=\frac{1.6\times {{10}^{6}}}{200\times 1.6\times {{10}^{-13}}}\] \[=5\times {{10}^{16}}\,{{s}^{-1}}\]


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