J & K CET Engineering J and K - CET Engineering Solved Paper-2008

  • question_answer
    The moment of inertia about an axis of a body which is rotating with angular velocity 1 rad/s is numerically equal to

    A) one-fourth of its rotational kinetic energy

    B) half of the rotational kinetic energy

    C) rotational kinetic energy

    D) twice the rotational kinetic energy

    Correct Answer: D

    Solution :

    Rotational kinetic energy, \[KE=\frac{1}{2}I{{\omega }^{2}}\] Here, \[\omega =1\,rad/s\] \[\therefore \] \[KE=\frac{1}{2}I\times 1\] or \[I=2\,KE\] ie, moment of inertia about an axis of a body is twice the rotational kinetic energy.


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