A) Tollen?s reagent
B) \[B{{r}_{2}}+{{H}_{2}}O\]
C) \[HN{{O}_{3}}\]
D) All of these
Correct Answer: C
Solution :
Tollen's reagent and bromine water both are mild oxidising agent, thus oxidise only aldehyde group. \[\text{HN}{{\text{O}}_{\text{3}}},\]being strong oxidizing agent, oxidises both the aldehyde as well as the primary alcoholic group and gives glucaric acid. \[(\underset{\text{glucose}}{\mathop{\underset{C{{H}_{2}}OH}{\overset{CHO}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,HOH)}}\,\xrightarrow[-{{H}_{2}}O]{HN{{O}_{3}}[3O]}\underset{\text{glucaric}\,\text{acid}}{\mathop{{{(\underset{C{{H}_{2}}OH}{\overset{COOH}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,HOH)}_{4}}}}\,\]
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