J & K CET Engineering J and K - CET Engineering Solved Paper-2009

  • question_answer
    If \[{{x}_{1}},{{x}_{2}},......{{x}_{18}}\] are observations such, that \[\sum\limits_{j=1}^{18}{({{x}_{j}}-8)=9}\] and \[\sum\limits_{j=1}^{18}{{{({{x}_{j}}-8)}^{2}}=45,}\] then the standard deviation of these observations is

    A)  \[\sqrt{\frac{81}{34}}\]           

    B)  \[5\]

    C)  \[\sqrt{5}\]

    D)  \[\frac{3}{2}\]

    Correct Answer: D

    Solution :

    Standard deviation \[=\sqrt{\frac{\underset{j=1}{\mathop{\overset{18}{\mathop{\Sigma }}\,}}\,{{({{x}_{j}}-8)}^{2}}}{n}-{{\left( \frac{\underset{j=1}{\mathop{\overset{18}{\mathop{\Sigma }}\,}}\,({{x}_{k}}-8)}{n} \right)}^{2}}}\] \[=\sqrt{\frac{45}{18}-{{\left( \frac{9}{18} \right)}^{2}}}\] \[=\sqrt{\frac{45}{18}-\frac{1}{4}}=\sqrt{\frac{81}{36}}=\frac{9}{6}=\frac{3}{2}\]


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