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J & K CET Engineering J and K - CET Engineering Solved Paper-2009

  • question_answer
    Two monoatomic ideal gases A and B occupying the same volume V, are at the same temperature T and pressure p. If they are mixed, the resultant mixture has volume V and temperature T. The pressure of the mixture is

    A)  \[P\]               

    B)  \[\frac{P}{2}\]

    C)  \[4\,P\]            

    D)  \[2\,P\]

    Correct Answer: D

    Solution :

    \[\frac{{{p}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{p}_{mix}}\times {{V}_{mix}}}{{{T}_{mix}}}\] Here, \[{{T}_{1}}={{T}_{mis}}=T\] \[{{V}_{1}}=V+V\] \[{{V}_{mix}}=V\] \[\therefore \] \[\frac{p\times 2V}{T}=\frac{{{p}_{mix}}\times V}{T}\] \[\Rightarrow \] \[{{p}_{mix}}=2p\]


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