J & K CET Engineering J and K - CET Engineering Solved Paper-2009

  • question_answer
    The relation connecting magnetic susceptibility \[{{\chi }_{m}}\]and relative permeability \[{{\mu }_{r}}\] is

    A)  \[{{\chi }_{m}}={{\mu }_{r}}+1\]

    B)  \[{{\chi }_{m}}={{\mu }_{r}}-1\]

    C)  \[{{\chi }_{m}}=\frac{1}{{{\mu }_{r}}}\]

    D)  \[{{\chi }_{m}}=3(1+{{\mu }_{r}})\]

    Correct Answer: B

    Solution :

    Total magnetic flux density B in a material is the sum of magnetic flux density in vacuum \[{{B}_{0}}\] produced by magnetising force and magnetic flux density due to magnetisation of material \[{{B}_{m}}\] ie, \[B={{B}_{0}}+{{B}_{m}}\] \[\Rightarrow \] \[B={{\mu }_{0}}H+{{\mu }_{0}}I={{\mu }_{0}}(H+I)\] \[={{\mu }_{0}}H(1+{{\chi }_{m}})\] Also      \[{{\mu }_{r}}=(1+{{\chi }_{m}})\]


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