question_answer

A uniformly wound coil of self-inductance \[1.2\times {{10}^{-4}}H\]and resistance \[3\Omega \]. is broken up into two identical coils. These coils are then connected parallel across a \[6V\]battery of negligible resistance. The time constant for the current in the circuit is (neglect mutual inductance)

A)  \[0.4\times {{10}^{-4}}s\]

B)  \[0.2\times {{10}^{-4}}\text{ }s\]

C)  \[0.5\times {{10}^{-4}}\text{ }s\]    

D)  \[0.1\times {{10}^{-4}}\text{ }s\]