A) \[CV\]
B) zero
C) \[\frac{1}{C{{V}^{2}}}\]
D) \[\frac{1}{4}C{{V}^{2}}\]
Correct Answer: B
Solution :
Average power in AC circuit is given by \[P={{V}_{rms}}\,{{I}_{rms}}\,\cos \phi \] For pure capacitive circuit \[\phi ={{90}^{o}}\] so \[P=0\].
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