A) current leads the voltage by \[{{45}^{o}}\]
B) voltage leads the current by \[{{90}^{o}}\]
C) current leads the voltage by \[{{90}^{o}}\]
D) voltage leads the current by \[{{45}^{o}}\]
Correct Answer: C
Solution :
The phase difference between instantaneous values of \[I\] and V is \[+\frac{\pi }{4}-\left( -\frac{\pi }{4} \right)=\frac{\pi }{2}\] Hence, current leads the voltage by \[{{90}^{o}}\].
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