A) twice the audio signal frequency
B) thrice the audio signal frequency
C) thrice the carrier wave frequency
D) twice the carrier wave frequency
Correct Answer: A
Solution :
In an AM wave, the bandwidth is from \[({{f}_{c}}-{{f}_{m}})\]to \[({{f}_{c}}-{{f}_{m}})\] ie, \[2{{f}_{m}},\] which is twice the signal frequency \[({{f}_{m}})\] [\[{{f}_{c}}\] is the carrier frequency].
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