A) B < D < A < C
B) C < A < D < B
C) D < B < C < A
D) A < C < D < B
Correct Answer: B
Solution :
Lower the value of standard enthalpy of formation, higher the stability. The increasing order of standard enthalpies of formation of given molecules is \[\underset{B(C{{O}_{2}})}{\mathop{-393.4}}\,<\underset{D(S{{O}_{2}})}{\mathop{296.9}}\,<\underset{A(N{{H}_{3}})}{\mathop{-46.19}}\,<+\,\underset{C(HI)}{\mathop{24.94}}\,\] Thus, the increasing order of stability is \[C<A<D<B\]
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