A) 2.0 g
B) 0.4 g
C) 4.0 g
D) 8.0 g
Correct Answer: C
Solution :
Since, same amount of current is passed for same time, \[\frac{{{w}_{H}}}{{{w}_{O}}}=\frac{{{E}_{H}}}{{{E}_{O}}}\] (Here, w represents mass and E represents equivalent mass.) \[\frac{0.504}{{{w}_{O}}}=\frac{{{E}_{H}}}{{{E}_{O}}}\] (Here,\[w\]represents mass and E represents equivalent mass.) \[\frac{0.504}{{{w}_{O}}}=\frac{1.008}{8}\] \[{{w}_{O}}=\frac{0.504\times 8}{1.008}=4.0\,g\]
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