A) 30.16
B) 2.55
C) 27.5
D) 37.5
Correct Answer: C
Solution :
At STP, \[\because \]Weight of 300 mL of gas\[~=0.368\text{ }g\] \[\therefore \]Weight of 22400 mL of gas \[=\frac{0.368\times 2240}{300}g/mol\] \[=27.47\,g/mol\] \[=27.5\,g/mol\] \[\because \]Molecular weight of the gas is 27.5. [\[\because \]22400 mL of a gas contains amount equal to molecular weight of the gas.]
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