J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    If \[|\vec{a}|=2,\,|\vec{b}|=5,\] and \[\vec{a}\,.\,\vec{b}=5\sqrt{2},\]then \[|\vec{a}\times \vec{b}|\] is equal to

    A)  \[5\sqrt{2}\]           

    B)  \[\sqrt{2}\]

    C)  \[4\sqrt{2}\]

    D)  \[2\]

    Correct Answer: A

    Solution :

    Given,  \[\vec{a}\,\,.\,\,\vec{b}\,\,=\,5\sqrt{2}\] \[|\vec{a}|\,\,|\vec{b}\,|\,\,\cos \,\theta =\,5\sqrt{2}\] \[\cos \,\theta =\frac{5\sqrt{2}}{2.5}=\frac{1}{\sqrt{2}}\] \[\theta ={{45}^{o}}\] Now, \[|\vec{a}\times \vec{b}|=|\vec{a}|\,\,|\vec{b}|\,\,\sin \theta \] \[=2.5.\sin \,{{45}^{o}}=\frac{10}{\sqrt{2}}=5\sqrt{2}\]


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