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J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    If 19 times 12th term of an AP and 18 times 11 th term of an AP are equal, then the 30th term of the AP is

    A)  \[0\]              

    B)  \[2\]

    C)  \[11\]             

    D)  \[29\]

    Correct Answer: A

    Solution :

    Let a and d be the first term and common difference cf the AP, then \[19\times {{T}_{12}}=18\times {{T}_{11}}\] \[19(a+11d)=18(a+10d)\] \[\Rightarrow \] \[19\,a+209\,d=18\,a+180d\] \[\Rightarrow \] \[a+29\,d=0\] \[\Rightarrow \] \[a+(30-1)d=0\] \[\Rightarrow \] \[{{T}_{30}}=0\]


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