J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    \[\underset{n\to \infty }{\mathop{\lim }}\,\,\,\frac{{{2}^{n+1}}+{{3}^{n+1}}}{{{2}^{n}}+{{3}^{n}}}\]is equal to

    A)  \[0\]               

    B)  \[1\]

    C)  \[2\]               

    D)  \[3\]

    Correct Answer: D

    Solution :

    \[\underset{n\to \infty }{\mathop{\lim }}\,\,\,\frac{{{2}^{n+1}}+{{3}^{n+1}}}{{{2}^{n}}+{{3}^{n}}}\] \[\underset{n\to \infty }{\mathop{\lim }}\,\,\,\,\frac{{{2.2}^{n}}+{{3.3}^{n}}}{{{2}^{n}}+{{3}^{n}}}\] \[=\underset{n\to \infty }{\mathop{\lim }}\,\,\,\frac{2.{{\left( \frac{2}{3} \right)}^{n}}+3}{{{\left( \frac{2}{3} \right)}^{n}}+1}\] \[=\frac{0+3}{0+1}=3\]


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