A) \[{{270}^{o}}C\]and \[{{530}^{o}}C\]
B) \[{{270}^{o}}C\] and \[{{550}^{o}}C\]
C) \[{{280}^{o}}C\]and \[{{530}^{o}}C\]
D) \[{{280}^{o}}C\]and \[{{550}^{o}}C\]
Correct Answer: A
Solution :
No change in neutral temperature but temperature of inversion is \[{{t}_{1}}=2{{t}_{n}}-{{t}_{c}}\] \[540=2{{t}_{n}}-{{0}^{o}}\] \[{{270}^{o}}C={{t}_{n}}\] \[{{t}_{i}}=2\times 270-10\] \[=540-10={{530}^{o}}C\]
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