A) 6
B) 2
C) 12
D) 7
Correct Answer: C
Solution :
\[0.05\text{ }M\text{ }{{H}_{2}}S{{O}_{4}}=0.05\times 2=0.1\text{ }N\text{ }{{H}_{2}}S{{O}_{4}}\] \[0.45\text{ }M\text{ }NaOH=0.45\times 1=0.45\text{ }N\text{ }NaOH\] \[\text{Meq}\text{. of}\,{{H}_{2}}S{{O}_{4}}=0.1\times 20=2\] \[\text{Meq}\text{. of }NaOH=0.45\times 5=2.25\] \[\text{Meq, of }NaOH\text{ left}=2.25-2=0.25\] Hence, resulting solution is alkaline in nature.
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