A) \[n-\]hexane
B) 2, 2-dimethylbutane
C) 2, 3-dimethylbutane
D) 3-methylpentane
Correct Answer: C
Solution :
2,3-dimethylbutane has 12 equivalent \[\text{1}{{\,}^{\text{o}}}\text{H}\]and two equivalent\[3{{\,}^{\text{o}}}\text{H}\]hence it gives two constitutionally isomeric monochlorides of molecular formulae \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{13}}}\text{Cl}\text{.}\] \[\underset{2,3-\text{dimethyl}\,\text{butane}}{\mathop{C{{H}_{3}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}}}\,\xrightarrow[\text{Heat}]{\text{C}{{\text{l}}_{\text{2}}}\text{,Light}}\] \[C{{H}_{3}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-C{{H}_{2}}Cl\] \[+\,C{{H}_{3}}-\underset{Cl}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}\]
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