A) \[10\text{ }mm\]
B) \[0.5\text{ }mm\]
C) \[20\,\,mm\]
D) \[15\,\,mm\]
Correct Answer: B
Solution :
Given \[d=1\times {{10}^{-3}}m,\,\,\lambda =500\times {{10}^{-9}}m\] and \[D=1m\]. Fringe separation \[\beta =\frac{\lambda D}{d}\] \[=\frac{500\times {{10}^{-9}}\times 1}{1\times {{10}^{-3}}}\] \[=500\times {{10}^{-6}}\] \[=0.5\times {{10}^{-3}}m\] \[=0.5mm\]
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