A) \[\log \frac{m}{x}=\log K+\frac{1}{m}\log p\]
B) \[\log \frac{x}{m}=\log K+n\log p\]
C) \[\log \frac{m}{x}=\log K+n\log p\]
D) \[\log \frac{x}{m}=\log K+\frac{1}{n}\log p\]
Correct Answer: D
Solution :
Freundlich adsorption isotherm equation is as \[\log \frac{x}{m}=\log \,k+\frac{1}{n}\log p\] where\[x\]is the mass of the gas adsorbed on mass m of the adsorbent at pressure p. k and n are constants.
You need to login to perform this action.
You will be redirected in
3 sec
