J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer The equation of the line passing through \[(0,0)\]and intersection of \[3x-4y=2\]and \[x+2y=-4\]is

    A)  \[7x=6y\]                                     

    B)  \[6x=7y\]

    C)  \[5x=8y\]         

    D)  \[x=0\]

    Correct Answer: A

    Solution :

    Given lines, \[3x-4y=2\] ?.(i) \[x+2y=-4\] ?.(ii) Intersection point of these line is \[3(-4-2y)-4y=2\] \[-12-6y-4y=2\] \[10y=-14\,\,\,\,\Rightarrow \,\,\,y=-7/5\] and \[x=-4-2(-7/5)=-4+14/5\] \[x=-6/5\] Intersection point is \[(-6/5,\,\,-7/5)\]. Now, the equation of the line which passes through the points \[(0,0)\] and \[(-6/5,\,-7/5)\]. \[\Rightarrow \] \[(y-0)+\frac{-7/5-0}{-6/5-0}(x-0)\] \[\Rightarrow \] \[y=\frac{7}{6}.x\] \[\Rightarrow \]                          \[7x=6y\]

adversite


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