A) \[-3,\,1+2\omega ,\,1+2{{\omega }^{2}}\]
B) \[-3,\,1-2\,\omega ,\,1-2{{\omega }^{2}}\]
C) \[-3,-1+2\omega ,-1+2{{\omega }^{2}}\]
D) \[-3,-1-2\omega ,-1-2{{\omega }^{2}}\]
Correct Answer: D
Solution :
Given, \[\omega \to \] cube root of units \[\Rightarrow \] \[{{(x+1)}^{3}}+8=0\] So, the roots of above equation is, \[(x+1)=-2,\,-2\omega ,\,-2{{\omega }^{2}}\] \[\Rightarrow \] \[x=-3,\,\,-1-2\omega ,-1-2{{\omega }^{2}}\]
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