A) \[\frac{1}{7\,\,!}\]
B) \[\frac{8}{35}\]
C) \[\frac{19}{35}\]
D) \[\frac{27}{35}\]
Correct Answer: D
Solution :
Required probability \[^{4}{{C}_{1}}\times {{(}^{2}}{{C}_{0}}{{\times }^{2}}{{C}_{1}}{{\times }^{2}}{{C}_{1}}{{+}^{2}}{{C}_{1}}{{\times }^{2}}{{C}_{0}}{{\times }^{2}}{{C}_{1}}\]\[=\frac{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{+}^{2}}{{C}_{1}}{{\times }^{2}}{{C}_{1}}{{\times }^{2}}{{C}_{0}}){{\,}^{4}}{{C}_{2}}\,\,\,\,\,\,\,\,\,}{^{8}{{C}_{4}}}\] \[=\frac{4(2\times 2\times 1+2\times 1\times 2+2\times 2\times 1)+6}{70}\] \[=\frac{4(4+4+4)+6}{70}=\frac{48+6}{70}=\frac{54}{70}=\frac{27}{35}\]
You need to login to perform this action.
You will be redirected in
3 sec
