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J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer
    When the current changes form \[+2A\]to \[-3A\] in \[0.05,\]an emf of \[8\text{ }V\]is induced in a coil. The coefficient of self inductance of the coil is

    A)  \[0.2\text{ }H\]          

    B)  \[0.4\text{ }H\]

    C)  \[0.8\text{ }H\]           

    D)  \[0.1\text{ }H\]

    Correct Answer: D

    Solution :

    \[e=L\frac{di}{dt}\] \[8=\frac{L[2-(-2)]}{0.05}\] \[8=\frac{L\times 4}{0.05}\] \[L=\frac{8\times 0.05}{4}\] The coefficient of self inductance, \[L=0.1H\]


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