J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer A car moving with a speed of \[50\text{ }km/h\]can be stopped by brakes, over a distance of \[6m\]. If the same car is moving at a speed of \[100\text{ }km/h,\] the stopping distance is

    A)   \[12\text{ }m\]

    B)  \[18\text{ }m\]

    C)  \[6\text{ }m\]

    D)  \[24\text{ }m\]

    Correct Answer: D

    Solution :

    Case I. \[{{v}^{2}}={{u}^{2}}-2as\] \[0={{(50)}^{2}}-2\times a\times \frac{6}{1000}\] \[\frac{2\times a\times 6}{1000}=50\times 50\] \[a=\frac{50\times 50\times 1000}{2\times 6}\] Case II. \[{{v}^{2}}={{u}^{2}}-2as\] \[0={{(100)}^{2}}-2\times \frac{50\times 50\times 1000}{2\times 6}\times 5\] \[s=\frac{100\times 100\times 6}{50\times 50\times 1000}\] \[s=\frac{24}{1000}km\] \[s=24m\]


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