J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer A cubical block rests on an inclined plane of coefficient of friction \[\mu =1/\sqrt{3}\]. What should be the angle of inclination so that the block Just slides down the inclined plane?

    A)  \[{{30}^{o}}\]              

    B)  \[{{60}^{o}}\]

    C)  \[{{45}^{o}}\]             

    D)  \[{{90}^{o}}\]

    Correct Answer: A

    Solution :

    \[\tan \,\,\theta =\mu \] \[\tan \theta =\frac{1}{\sqrt{3}}\] \[\tan \theta =\tan \,{{30}^{o}}\] Angle of inclination, \[\theta ={{30}^{o}}\]

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