• # question_answer A cubical block rests on an inclined plane of coefficient of friction $\mu =1/\sqrt{3}$. What should be the angle of inclination so that the block Just slides down the inclined plane? A)  ${{30}^{o}}$               B)  ${{60}^{o}}$ C)  ${{45}^{o}}$              D)  ${{90}^{o}}$

$\tan \,\,\theta =\mu$ $\tan \theta =\frac{1}{\sqrt{3}}$ $\tan \theta =\tan \,{{30}^{o}}$ Angle of inclination, $\theta ={{30}^{o}}$