A) \[B{{F}_{3}}>BC{{l}_{3}}>BB{{r}_{3}}>B{{I}_{3}}\]
B) \[B{{I}_{3}}>BC{{l}_{3}}>BB{{r}_{3}}>B{{F}_{3}}\]
C) \[B{{I}_{3}}>BB{{r}_{3}}>BC{{l}_{3}}>B{{F}_{3}}\]
D) \[BC{{l}_{3}}>B{{F}_{3}}>BB{{r}_{3}}>B{{I}_{3}}\]
Correct Answer: C
Solution :
The correct order of decreasing Lewis acidity is \[B{{I}_{3}}>BB{{r}_{3}}>BC{{l}_{3}}>B{{F}_{3}}\] This is due to back bonding that takes place in \[\text{B}{{\text{F}}_{\text{3}}}\]molecule (maximum) due to comparable size of p-orbitals of fluorine and boron and maker it less electron deficient.
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