J & K CET Engineering J and K - CET Engineering Solved Paper-2012

  • question_answer
    If \[f(x)=\sin \left\{ \log \left( \frac{\sqrt{16-{{x}^{2}}}}{2-x} \right) \right\},\] then domain of \[f(x)\] is equal to

    A)  \[(-4,\,2)\]          

    B)  \[(-4,\,\,4)\]

    C)  \[(-4,\,\,4]\]          

    D)  \[[-4,\,\,4]\]

    Correct Answer: A

    Solution :

    Given,   \[f(x)=\sin \left\{ \log \,\,\left( \frac{\sqrt{16-{{x}^{2}}}}{2-x} \right) \right\}\] For \[f(x)\] to be defined, \[2-x>0\] and \[16-{{x}^{2}}>0\] \[\Rightarrow \] \[x<2\] and \[{{x}^{2}}<16\] \[\Rightarrow \] \[x<1\] and \[-4<x<4\] \[\Rightarrow \] \[-4<x<2\]


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