J & K CET Engineering J and K - CET Engineering Solved Paper-2012

  • question_answer
    Totally unpolarized light of intensity \[{{I}_{0}}\] is incident normally on a polarizer and the emerging light is made to pass through a second, parallel polarizer with its axis making an angle of 60° with that of the first. What is the intensity of light emerging out of the second polarizer?

    A)  Zero

    B)  \[\frac{{{I}_{0}}}{8}\]

    C)  \[\frac{{{I}_{0}}}{4}\]

    D)  \[\frac{{{I}_{0}}}{16}\]

    Correct Answer: B

    Solution :

    Intensity of light emerging out from the first polarizer \[{{I}_{1}}=\frac{1}{2}{{I}_{0}}\] The intensity of light emerging out from the second polarizer \[{{I}_{2}}={{I}_{1}}\,\,{{\cos }^{2}}\,\,{{60}^{o}}\] \[=\left( \frac{1}{2}{{I}_{0}} \right){{\left( \frac{1}{2} \right)}^{2}}\] \[{{I}_{2}}=\frac{1}{8}{{I}_{0}}\]


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