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J & K CET Engineering J and K - CET Engineering Solved Paper-2012

  • question_answer
    A first order reaction has a rate constant \[k=3.01\times {{10}^{-3}}/s.\]How long it will take to decompose half of the reaction?

    A) \[2.303\text{ }s\]         

    B) \[~23.03\text{ }s\]

    C) \[~230.23s\]        

    D) \[~2303s\]

    Correct Answer: C

    Solution :

     \[k=3.01\times {{10}^{-3}}{{s}^{-1}}\] \[{{t}_{1/2}}=?\] \[k=\frac{0.693}{{{t}_{1/2}}}\](for a first order reaction) \[\therefore \] \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{3.01\times {{10}^{-3}}}\]


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