A) \[CH\equiv CH\]
B) \[C{{H}_{2}}=CH-CHO\]
C) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
D) \[C{{H}_{3}}-CH=CH-COOH\]
Correct Answer: C
Solution :
Propene has only one \[\pi -\]electron.
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