question_answer

The number of optical isomers of the compound\[C{{H}_{3}}CHBrCHBrCOOH\]is

A)  0                      

B)  1

C)  3                     

D)  4

Correct Answer: D

Solution :

 Those compounds having two dissimilar asymmetric carbon atoms show four optical Isomers as follows \[({{2}^{2}}=4)\]