A) hydrochloric acid in the presence of nitrous acid
B) cuprous chloride in the presence of aluminium chloride
C) chlorine in the presence of aluminium chloride
D) nitrous acid followed by heating with cuprous chloride
Correct Answer: D
Solution :
\[{{\text{C}}_{6}}{{H}_{5}}N{{H}_{2}}.HCl+HN{{O}_{2}}\xrightarrow{0{{\,}^{o}}C}\underset{\begin{smallmatrix} \text{benzene}\,\text{dizonium} \\ \,\,\,\,\,\,\,\,\,\,\,\text{chloride} \end{smallmatrix}}{\mathop{{{C}_{6}}{{H}_{5}}{{N}_{2}}Cl}}\,\] \[\xrightarrow[or\,Cu+HCl\,\text{warm}]{CuCl}\underset{\text{chlorobenzene}}{\mathop{{{C}_{6}}{{H}_{5}}Cl}}\,\,+\,{{N}_{2}}\] .
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