A) \[1.2\times {{10}^{-3}}N\]
B) \[12\times {{10}^{-3}}N\]
C) \[11.2\times {{10}^{-3}}\text{ }N\]
D) \[10.2\times {{10}^{-3}}\text{ }N\]
Correct Answer: A
Solution :
Force between two parallel wires is \[F=\frac{{{\mu }_{0}}}{4\pi }.\frac{2{{I}_{1}}{{I}_{2}}}{r}.l\] Given, \[{{\mu }_{0}}=4\pi \times {{10}^{-7}},{{I}_{1}}=30A,\,\,{{I}_{2}}=40A,\] \[l=10\times {{10}^{-2}}m,\,\,r-2\times {{10}^{-2}}m\] \[F=\frac{4\pi \times {{10}^{-7}}}{4\pi }\times \frac{2\times 30\times 40}{2\times {{10}^{-2}}}\times \frac{10}{100}\] \[\Rightarrow \] \[F=1.2\times {{10}^{-3}}N\]
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