A) \[-437\,kJ\]
B) \[135\,kJ\]
C) \[-135\,kJ\]
D) None of these
Correct Answer: C
Solution :
According to available data (i) \[{{C}_{2}}{{H}_{4}}(g)+3{{O}_{2}}(g)\xrightarrow{{}}2C{{O}_{2}}(g)+2{{H}_{2}}O(l)\] \[\Delta H=-1415\,kJ\] (ii)\[{{C}_{2}}{{H}_{6}}(g)+\frac{7}{2}{{O}_{2}}(g)\xrightarrow{{}}2C{{O}_{2}}(g)+3{{H}_{2}}O(l)\] \[\Delta H=-1566\,kJ\] (iii) \[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}{{H}_{2}}O(l);\Delta H=-286\,kJ\] We aim at \[{{C}_{2}}{{H}_{4}}(g)+{{H}_{2}}(g)\xrightarrow{{}}{{C}_{2}}{{H}_{6}}(g);\Delta H?\] Eq. (i) + Eq. (iii) - Eq. (ii) and the correct \[\Delta H\]value is \[=(-1415)+(-286)-(-1566)\] \[=-135\,kJ\]
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