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J & K CET Engineering J and K - CET Engineering Solved Paper-2014

  • question_answer
    For what values of x, the numbers \[-1,\,x,-3/4\] are in GP?

    A)  \[3/2\]              

    B)  \[\sqrt{3}/4\]

    C)  \[\sqrt{3}/2\]            

    D)  \[3/\sqrt{2}\]

    Correct Answer: C

    Solution :

    Given,  \[-1,x,\frac{-3}{4}\] are in GP \[\therefore \] \[{{x}^{2}}=(-1)\left( \frac{-3}{4} \right)\] \[\Rightarrow \] \[x=\sqrt{\frac{3}{4}}\]    \[\Rightarrow \]   \[x=\frac{\sqrt{3}}{2}\]


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