A) \[22\]
B) \[18\]
C) \[20\]
D) \[25\]
E) None of these
Correct Answer: E
Solution :
Given, \[g(x)=({{x}^{2}}+2x+3)f(x),f(0)=5\] and \[\underset{x\to 0}{\mathop{\lim }}\,\,\,\left[ \frac{f(x)-5}{x} \right]=4\] \[f'(0)=\underset{x\to 0}{\mathop{\lim }}\,\,\,\frac{f(0+x)-f(0)}{x-0}\] \[=\underset{x-0}{\mathop{\lim }}\,\frac{f(x)-5}{x}\] \[\Rightarrow \] \[f'(0)=4\]You need to login to perform this action.
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