A) \[x\in (-\infty ,\,4)\]
B) \[x\in (-\infty ,\,4]\]
C) \[x\in (-\infty ,\,8]\]
D) \[x\in (-\infty ,\,-4]\]
Correct Answer: B
Solution :
Given, \[2x-5\le \frac{(4x-7)}{3}\] \[\Rightarrow \] \[6x-15\le 4x-7\] \[\Rightarrow \] \[6x-4x\le -7+15\] \[\Rightarrow \] \[2x\le 8\] \[\Rightarrow \] \[x\le \frac{8}{2}\,\,\,\,\,\Rightarrow \,\,\,\,\,\,x\le 4\] \[\therefore \] \[x\in (-\infty ,\,4]\]
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