• # question_answer Solve the equation ${{x}^{2}}-\sqrt{3}x+1=0$ A)  $x=(-\sqrt{3}\,\,\pm \,\,2i)/2$   B)  $x=(-\sqrt{3}\,\,\pm \,i)/2$ C)  $x=(-\sqrt{3}\,\,\pm \,i)$      D)  $x=(\sqrt{3}\,\,\pm \,i)/2$

Given equation is ${{x}^{2}}-\sqrt{3}x+1=0$ $\therefore$ $x=\frac{+\sqrt{3}\pm \sqrt{{{(-\sqrt{3})}^{2}}-4}}{2}$ $=\frac{\sqrt{3}\pm \sqrt{3-4}}{2}=\frac{\sqrt{3}\pm i}{2}$