A) \[18\,\mu \,C/m\]
B) \[5\,\mu \,C/m\]
C) \[4\,\mu \,C/m\]
D) \[10\,\mu \,C/m\]
Correct Answer: C
Solution :
For a infinite line charge, \[E=\frac{2\lambda }{4\pi {{\varepsilon }_{0}}r}\] \[\lambda =E(2\pi {{\varepsilon }_{0}}r)\] \[=\frac{18\times {{10}^{5}}\times (4\times {{10}^{-2}})}{2\times 9\times 10h9}\] \[=4\times {{10}^{-6}}\,C/m\] \[=4\,\,C/m\]
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